Van Lamoen circle

The van Lamoen circle through six circumcenters A b {\displaystyle A_{b}} , A c {\displaystyle A_{c}} , B c {\displaystyle B_{c}} , B a {\displaystyle B_{a}} , C a {\displaystyle C_{a}} , C b {\displaystyle C_{b}}

In Euclidean plane geometry, the van Lamoen circle is a special circle associated with any given triangle T {\displaystyle T} . It contains the circumcenters of the six triangles that are defined inside T {\displaystyle T} by its three medians.[1][2]

Specifically, let A {\displaystyle A} , B {\displaystyle B} , C {\displaystyle C} be the vertices of T {\displaystyle T} , and let G {\displaystyle G} be its centroid (the intersection of its three medians). Let M a {\displaystyle M_{a}} , M b {\displaystyle M_{b}} , and M c {\displaystyle M_{c}} be the midpoints of the sidelines B C {\displaystyle BC} , C A {\displaystyle CA} , and A B {\displaystyle AB} , respectively. It turns out that the circumcenters of the six triangles A G M c {\displaystyle AGM_{c}} , B G M c {\displaystyle BGM_{c}} , B G M a {\displaystyle BGM_{a}} , C G M a {\displaystyle CGM_{a}} , C G M b {\displaystyle CGM_{b}} , and A G M b {\displaystyle AGM_{b}} lie on a common circle, which is the van Lamoen circle of T {\displaystyle T} .[2]

History

The van Lamoen circle is named after the mathematician Floor van Lamoen [nl] who posed it as a problem in 2000.[3][4] A proof was provided by Kin Y. Li in 2001,[4] and the editors of the Amer. Math. Monthly in 2002.[1][5]

Properties

The center of the van Lamoen circle is point X ( 1153 ) {\displaystyle X(1153)} in Clark Kimberling's comprehensive list of triangle centers.[1]

In 2003, Alexey Myakishev and Peter Y. Woo proved that the converse of the theorem is nearly true, in the following sense: let P {\displaystyle P} be any point in the triangle's interior, and A A {\displaystyle AA'} , B B {\displaystyle BB'} , and C C {\displaystyle CC'} be its cevians, that is, the line segments that connect each vertex to P {\displaystyle P} and are extended until each meets the opposite side. Then the circumcenters of the six triangles A P B {\displaystyle APB'} , A P C {\displaystyle APC'} , B P C {\displaystyle BPC'} , B P A {\displaystyle BPA'} , C P A {\displaystyle CPA'} , and C P B {\displaystyle CPB'} lie on the same circle if and only if P {\displaystyle P} is the centroid of T {\displaystyle T} or its orthocenter (the intersection of its three altitudes).[6] A simpler proof of this result was given by Nguyen Minh Ha in 2005.[7]

See also

  • Parry circle
  • Lester circle

References

  1. ^ a b c Kimberling, Clark, Encyclopedia of Triangle Centers, retrieved 2014-10-10. See X(1153) = Center of the van Lemoen circle.
  2. ^ a b Weisstein, Eric W., "van Lamoen circle", MathWorld, retrieved 2014-10-10
  3. ^ van Lamoen, Floor (2000), Problem 10830, vol. 107, American Mathematical Monthly, p. 893
  4. ^ a b Li, Kin Y. (2001), "Concyclic problems" (PDF), Mathematical Excalibur, 6 (1): 1–2
  5. ^ (2002), Solution to Problem 10830. American Mathematical Monthly, volume 109, pages 396-397.
  6. ^ Myakishev, Alexey; Woo, Peter Y. (2003), "On the Circumcenters of Cevasix Configuration" (PDF), Forum Geometricorum, 3: 57–63
  7. ^ Ha, N. M. (2005), "Another Proof of van Lamoen's Theorem and Its Converse" (PDF), Forum Geometricorum, 5: 127–132