Seymourville, West Virginia

Unincorporated community in West Virginia, United States
39°03′25″N 79°06′32″W / 39.05694°N 79.10889°W / 39.05694; -79.10889CountryUnited StatesStateWest VirginiaCountyGrantElevation1,030 ft (310 m)Time zoneUTC-5 (Eastern (EST)) • Summer (DST)UTC-4 (EDT)Area code(s)304 & 681GNIS feature ID1555594[1]

Seymourville is an unincorporated community in Grant County, West Virginia, United States. Seymourville is 4.5 miles (7.2 km) north of Petersburg.

References

  1. ^ a b U.S. Geological Survey Geographic Names Information System: Seymourville, West Virginia
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Municipalities and communities of Grant County, West Virginia, United States
County seat: Petersburg
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Map of West Virginia highlighting Grant County
Town
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Unincorporated
communitiesFootnotes
‡This populated place also has portions in an adjacent county or counties
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