Metallic mean

Generalization of golden and silver ratios
Gold, silver, and bronze ratios within their respective rectangles.

The metallic mean (also metallic ratio, metallic constant, or noble means[1]) of a natural number n is a positive real number, denoted here S n , {\displaystyle S_{n},} that satisfies the following equivalent characterizations:

  • the unique positive real number x {\displaystyle x} such that x = n + 1 x {\textstyle x=n+{\frac {1}{x}}}
  • the positive root of the quadratic equation x 2 n x 1 = 0 {\displaystyle x^{2}-nx-1=0}
  • the number n + n 2 + 4 2 {\textstyle {\frac {n+{\sqrt {n^{2}+4}}}{2}}}
  • the number whose expression as a continued fraction is
    [ n ; n , n , n , n , ] = n + 1 n + 1 n + 1 n + 1 n + {\displaystyle [n;n,n,n,n,\dots ]=n+{\cfrac {1}{n+{\cfrac {1}{n+{\cfrac {1}{n+{\cfrac {1}{n+\ddots \,}}}}}}}}}

Metallic means are generalizations of the golden ratio ( n = 1 {\displaystyle n=1} ) and silver ratio ( n = 2 {\displaystyle n=2} ), and share some of their interesting properties. The term "bronze ratio" ( n = 3 {\displaystyle n=3} ), and terms using other metals names (such as copper or nickel), are occasionally used to name subsequent metallic means.[2] [3]

In terms of algebraic number theory, the metallic means are exactly the real quadratic integers that are greater than 1 {\displaystyle 1} and have 1 {\displaystyle -1} as their norm.

The defining equation x 2 n x 1 = 0 {\displaystyle x^{2}-nx-1=0} of the nth metallic mean is the characteristic equation of a linear recurrence relation of the form x k = n x k 1 + x k 2 . {\displaystyle x_{k}=nx_{k-1}+x_{k-2}.} It follows that, given such a recurrence the solution can be expressed as

x k = a S n k + b ( 1 S n ) k , {\displaystyle x_{k}=aS_{n}^{k}+b\left({\frac {-1}{S_{n}}}\right)^{k},}

where S n {\displaystyle S_{n}} is the nth metallic mean, and a and b are constants depending only on x 0 {\displaystyle x_{0}} and x 1 . {\displaystyle x_{1}.} Since the inverse of a metallic mean is less than 1, this formula implies that the quotient of two consecutive elements of such a sequence tends to the metallic mean, when k tends to the infinity.

For example, if n = 1 , {\displaystyle n=1,} S n {\displaystyle S_{n}} is the golden ratio. If x 0 = 0 {\displaystyle x_{0}=0} and x 1 = 1 , {\displaystyle x_{1}=1,} the sequence is the Fibonacci sequence, and the above formula is Binet's formula. If n = 1 , x 0 = 2 , x 1 = 1 {\displaystyle n=1,x_{0}=2,x_{1}=1} one has the Lucas numbers. If n = 2 , {\displaystyle n=2,} the metallic mean is called the silver ratio, and the elements of the sequence starting with x 0 = 0 {\displaystyle x_{0}=0} and x 1 = 1 {\displaystyle x_{1}=1} are called the Pell numbers. The third metallic mean is sometimes called the "bronze ratio".

Geometry

If one removes n largest possible squares from a rectangle with ratio length/width equal to the nth metallic mean, one gets a rectangle with the same ratio length/width (in the figures, n is the number of dotted lines).
Golden ratio within the pentagram (φ = red/ green = green/blue = blue/purple) and silver ratio within the octagon.

The defining equation x = n + 1 x {\textstyle x=n+{\frac {1}{x}}} of the nth metallic mean induces the following geometrical interpretation.

Consider a rectangle such that the ratio of its length L to its width W is the nth metallic ratio. If one remove from this rectangle n squares of side length W, one gets a rectangle similar to the original rectangle; that is, a rectangle with the same ratio of the length to the width (see figures).

The nth metallic ratio is the arithmetic mean of the hypothenuse and the shortest leg of a right triangle with side lengths of 2 and n. This results from the value n + n 2 + 4 2 {\displaystyle {\frac {n+{\sqrt {n^{2}+4}}}{2}}} and the Pythagorean theorem.

Some metallic means appear as segments in the figure formed by a regular polygon and its diagonals. This is in particular the case for the golden ratio and the pentagon, and for the silver ratio and the octagon; see figures.

Powers


Denoting by S m {\displaystyle S_{m}} the metallic mean of m one has

S m n = K n S m + K n 1 , {\displaystyle S_{m}^{n}=K_{n}S_{m}+K_{n-1},}

where the numbers K n {\displaystyle K_{n}} are defined recursively by the initial conditions K0 = 0 and K1 = 1, and the recurrence relation

K n = m K n 1 + K n 2 . {\displaystyle K_{n}=mK_{n-1}+K_{n-2}.}

Proof: The equality is immediately true for n = 1. {\displaystyle n=1.} The recurrence relation implies K 2 = m , {\displaystyle K_{2}=m,} which makes the equality true for k = 2. {\displaystyle k=2.} Supposing the equality true up to n 1 , {\displaystyle n-1,} one has

S m n = m S m n 1 + S m n 2 (defining equation) = m ( K n 1 S n + K n 2 ) + ( K n 2 S m + K n 3 ) (recurrence hypothesis) = ( m K n 1 + K n 2 ) S n + ( m K n 2 + K n 3 ) (regrouping) = K n S m + K n 1 (recurrence on  K n ) . {\displaystyle {\begin{aligned}S_{m}^{n}&=mS_{m}^{n-1}+S_{m}^{n-2}&&{\text{(defining equation)}}\\&=m(K_{n-1}S_{n}+K_{n-2})+(K_{n-2}S_{m}+K_{n-3})&&{\text{(recurrence hypothesis)}}\\&=(mK_{n-1}+K_{n-2})S_{n}+(mK_{n-2}+K_{n-3})&&{\text{(regrouping)}}\\&=K_{n}S_{m}+K_{n-1}&&{\text{(recurrence on }}K_{n}).\end{aligned}}}

End of the proof.

One has also [citation needed]

K n = S m n + 1 ( m S m ) n + 1 m 2 + 4 . {\displaystyle K_{n}={\frac {S_{m}^{n+1}-(m-S_{m})^{n+1}}{\sqrt {m^{2}+4}}}.}

The odd powers of a metallic mean are themselves metallic means. More precisely, if n is an odd natural number, then S m n = S M n , {\displaystyle S_{m}^{n}=S_{M_{n}},} where M n {\displaystyle M_{n}} is defined by the recurrence relation M n = m M n 1 + M n 2 {\displaystyle M_{n}=mM_{n-1}+M_{n-2}} and the initial conditions M 0 = 2 {\displaystyle M_{0}=2} and M 1 = m . {\displaystyle M_{1}=m.}

Proof: Let a = S m {\displaystyle a=S_{m}} and b = 1 / S m . {\displaystyle b=-1/S_{m}.} The definition of metallic means implies that a + b = m {\displaystyle a+b=m} and a b = 1. {\displaystyle ab=-1.} Let M n = a n + b n . {\displaystyle M_{n}=a^{n}+b^{n}.} Since a n b n = ( a b ) n = 1 {\displaystyle a^{n}b^{n}=(ab)^{n}=-1} if n is odd, the power a n {\displaystyle a^{n}} is a root of x 2 M n 1 = 0. {\displaystyle x^{2}-M_{n}-1=0.} So, it remains to prove that M n {\displaystyle M_{n}} is an integer that satisfies the given recurrence relation. This results from the identity

a n + b n = ( a + b ) ( a n 1 + b n 1 ) a b ( a n 2 + a n 2 ) = m ( a n 1 + b n 1 ) + ( a n 2 + a n 2 ) . {\displaystyle {\begin{aligned}a^{n}+b^{n}&=(a+b)(a^{n-1}+b^{n-1})-ab(a^{n-2}+a^{n-2})\\&=m(a^{n-1}+b^{n-1})+(a^{n-2}+a^{n-2}).\end{aligned}}}

This completes the proof, given that the initial values are easy to verify.

In particular, one has

S m 3 = S m 3 + 3 m S m 5 = S m 5 + 5 m 3 + 5 m S m 7 = S m 7 + 7 m 5 + 14 m 3 + 7 m S m 9 = S m 9 + 9 m 7 + 27 m 5 + 30 m 3 + 9 m S m 11 = S m 11 + 11 m 9 + 44 m 7 + 77 m 5 + 55 m 3 + 11 m {\displaystyle {\begin{aligned}S_{m}^{3}&=S_{m^{3}+3m}\\S_{m}^{5}&=S_{m^{5}+5m^{3}+5m}\\S_{m}^{7}&=S_{m^{7}+7m^{5}+14m^{3}+7m}\\S_{m}^{9}&=S_{m^{9}+9m^{7}+27m^{5}+30m^{3}+9m}\\S_{m}^{11}&=S_{m^{11}+11m^{9}+44m^{7}+77m^{5}+55m^{3}+11m}\end{aligned}}}

and, in general,[citation needed]

S m 2 n + 1 = S M , {\displaystyle S_{m}^{2n+1}=S_{M},}

where

M = k = 0 n 2 n + 1 2 k + 1 ( n + k 2 k ) m 2 k + 1 . {\displaystyle M=\sum _{k=0}^{n}{{2n+1} \over {2k+1}}{{n+k} \choose {2k}}m^{2k+1}.}

For even powers, things are more complicate. If n is a positive even integer then[citation needed]

S m n S m n = 1 S m n . {\displaystyle {S_{m}^{n}-\left\lfloor S_{m}^{n}\right\rfloor }=1-S_{m}^{-n}.}

Additionally,[citation needed]

1 S m 4 S m 4 + S m 4 1 = S ( m 4 + 4 m 2 + 1 ) {\displaystyle {1 \over {S_{m}^{4}-\left\lfloor S_{m}^{4}\right\rfloor }}+\left\lfloor S_{m}^{4}-1\right\rfloor =S_{\left(m^{4}+4m^{2}+1\right)}}
1 S m 6 S m 6 + S m 6 1 = S ( m 6 + 6 m 4 + 9 m 2 + 1 ) . {\displaystyle {1 \over {S_{m}^{6}-\left\lfloor S_{m}^{6}\right\rfloor }}+\left\lfloor S_{m}^{6}-1\right\rfloor =S_{\left(m^{6}+6m^{4}+9m^{2}+1\right)}.}

Generalization

One may define the metallic mean S n {\displaystyle S_{-n}} of a negative integer n as the positive solution of the equation x 2 ( n ) 1. {\displaystyle x^{2}-(-n)-1.} The metallic mean of n is the multiplicative inverse of the metallic mean of n:

S n = 1 S n . {\displaystyle S_{-n}={\frac {1}{S_{n}}}.}

Another generalization consists of changing the defining equation from x 2 n x 1 = 0 {\displaystyle x^{2}-nx-1=0} to x 2 n x c = 0 {\displaystyle x^{2}-nx-c=0} . If

R = n ± n 2 + 4 c 2 , {\displaystyle R={\frac {n\pm {\sqrt {n^{2}+4c}}}{2}},}

is any root of the equation, one has

R n = c R . {\displaystyle R-n={\frac {c}{R}}.}

The silver mean of m is also given by the integral[citation needed]

S m = 0 m ( x 2 x 2 + 4 + m + 2 2 m ) d x . {\displaystyle S_{m}=\int _{0}^{m}{\left({x \over {2{\sqrt {x^{2}+4}}}}+{{m+2} \over {2m}}\right)}\,dx.}

Another form of the metallic mean is[citation needed]

n + n 2 + 4 2 = e a r s i n h ( n / 2 ) . {\displaystyle {\frac {n+{\sqrt {n^{2}+4}}}{2}}=e^{\operatorname {arsinh(n/2)} }.}

Numerical values

First metallic means[4][5]
N Ratio Value Name
0 0 + 4/2 1
1 1 + 5/2 1.618033989[a] Golden
2 2 + 8/2 2.414213562[b] Silver
3 3 + 13/2 3.302775638[c] Bronze
4 4 + 20/2 4.236067978[d]
5 5 + 29/2 5.192582404[e]
6 6 + 40/2 6.162277660[f]
7 7 + 53/2 7.140054945[g]
8 8 + 68/2 8.123105626[h]
9 9 + 85/2 9.109772229[i]
10 10+ 104/2 10.099019513[j]

See also

Notes

  1. ^ Sloane, N. J. A. (ed.). "Sequence A001622 (Decimal expansion of golden ratio phi (or tau) = (1 + sqrt(5))/2)". The On-Line Encyclopedia of Integer Sequences. OEIS Foundation.
  2. ^ OEIS: A014176, Decimal expansion of the silver mean, 1+sqrt(2).
  3. ^ OEIS: A098316, Decimal expansion of [3, 3, ...] = (3 + sqrt(13))/2.
  4. ^ OEIS: A098317, Decimal expansion of phi^3 = 2 + sqrt(5).
  5. ^ OEIS: A098318, Decimal expansion of [5, 5, ...] = (5 + sqrt(29))/2.
  6. ^ OEIS: A176398, Decimal expansion of 3+sqrt(10).
  7. ^ OEIS: A176439, Decimal expansion of (7+sqrt(53))/2.
  8. ^ OEIS: A176458, Decimal expansion of 4+sqrt(17).
  9. ^ OEIS: A176522, Decimal expansion of (9+sqrt(85))/2.
  10. ^ OEIS: A176537, Decimal expansion of (10+sqrt(104)/2.

References

  1. ^ M. Baake, U. Grimm (2013) Aperiodic order. Vol. 1. A mathematical invitation. With a foreword by Roger Penrose. Encyclopedia of Mathematics and its Applications, 149. Cambridge University Press, Cambridge, ISBN 978-0-521-86991-1.
  2. ^ de Spinadel, Vera W. (1999). "The metallic means family and multifractal spectra" (PDF). Nonlinear analysis, theory, methods and applications. 36 (6). Elsevier Science: 721–745.
  3. ^ de Spinadel, Vera W. (1998). Williams, Kim (ed.). "The Metallic Means and Design". Nexus II: Architecture and Mathematics. Fucecchio (Florence): Edizioni dell'Erba: 141–157.
  4. ^ Weisstein, Eric W. "Table of Silver means". MathWorld.
  5. ^ "An Introduction to Continued Fractions: The Silver Means", maths.surrey.ac.uk.

Further reading

  • Stakhov, Alekseĭ Petrovich (2009). The Mathematics of Harmony: From Euclid to Contemporary Mathematics and Computer Science, p. 228, 231. World Scientific. ISBN 9789812775832.

External links

  • Cristina-Elena Hrețcanu and Mircea Crasmareanu (2013). "Metallic Structures on Riemannian Manifolds", Revista de la Unión Matemática Argentina.
  • Rakočević, Miloje M. "Further Generalization of Golden Mean in Relation to Euler's 'Divine' Equation", Arxiv.org.